03-12-2010, 10:57 AM | #1 |
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Puzzle
There are 5 people in total. 3 Civilians, 1 Guard, 1 Cop
Three of the Civilians had to pay $10 each to the cop. The cop was being nice that day so he gave back $5 to the guard to give it back to the Civilians. However on the way back, the guard took $2 and gave $1 each to the Civilians. So in total the civilians only had to pay $9 each. Now if you combined $9 x 3 = $27, and if you add the $2 from the guard, making the total of $29. What happened to the $1??? I ran across this question before and I still can't figure it out... Anyone know? |
03-12-2010, 11:27 AM | #2 |
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Out of the 27$ paid by the civilians, 2$ out of that 27$ is with the guard, so it doesn't need to be added on top of the 27$. So the real question is where is the 3$? It's with the civilians.
Lol, they just throw you off by misleading you.
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03-12-2010, 11:54 AM | #5 |
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03-12-2010, 12:02 PM | #6 |
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Wow, I can't believe people really get stumped by elementry school math problems. What a sad world.
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03-12-2010, 12:41 PM | #8 | |
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Cop's total is $30 - $5 = $25 Guards's total is $5 - $3 = $2 Now for the basic math: Civilians total = (Cop + Guard total) $27 = (25 + 2) $27 = ($27) Totals equate to each other. Nothing is missing |
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03-12-2010, 03:06 PM | #10 | |
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03-12-2010, 04:05 PM | #12 |
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